CUET Preparation Today
If the matrix $A=\left[\begin{array}{cc}2-x & +3 \\ 2 & 1-x\end{array}\right]$ is singular, then value(s) of x are: |
1, 4 -1, 4 1, -4 2, -2 |
-1, 4 |
The correct answer is Option (2) → -1, 4 $|A|=0$ (singular) $(2-x)(1-x)-2×3=0$ $x^2-3x+2-6=0$ $x^2-3x-4=0$ $(x-4)(x+1)=0$ $x=4,-1$ |
