A uniform electric field pointing in positive X direction exists in a region Let O be the origin, A be the point on X axis at $x= +2 cm$ and B be the point on Y axis at $y = +1 cm$. Then potential at the point O, A and B satisfy:

$V_O>V_A$

The correct answer is Option (1) → $V_O>V_A$

Uniform electric field, $E=Ei$

Potential difference = $-\int E.dx$

Since, the electric field exists only along x-axis, the potential depends only on the x-coordinate and is dependent of y-coordinate.

$∴V_A-V_O=-E(x_A-x_O)$

$=V_O-E×0.02$

and,

Potential at O and B.

B is on the y-axis $(x=0,y=1)$

thus, 

$V_B=V_O$

$∴V_A<V_O=V_B$