The value of the integral $I=\int\limits_{-1}^1\left(x+x^3+x^5\right) dx$ is :
Answer & explanation
Correct answer: option 3
$I=\int\limits_{-1}^1\left(x+x^3+x^5\right) dx$
for odd functions
$\int\limits_{-a}^{a} f(x) dx = 0$
Let $\int f(x) dx = F(x)$
so if f(x) is odd. F(x) is even
so $\int\limits_{-a}^{a} f(x) dx = F(a) - F(-a)$
= 0
as (F(x) is even so F(x) = F(-x))
⇒ I = 0 + 0 + 0
= 0
since all are off function