A man’s present age is 125% of what it was 10 years ago, and 83\(\frac{1}{3}\)% of what it will be after 10 years. What is his present age?
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 50 years
Write the percentages as fractions: 125% \(=\frac{5}{4}\) and 83\(\frac{1}{3}\)% \(=\frac{5}{6}\). Let the present age be \(x\) years.
\(x=\tfrac{5}{4}(x-10)\), so \(4x=5x-50\) and \(x=50\)
The second condition agrees: \(\tfrac{5}{6}\times(50+10)=50\)
His present age is 50 years