If the height and slant height of a right circular cone are 8 cm and 10 cm, respectively, then the volume of the cone is (use π = $\frac{22}{7}$ ): ( correct the two decimal places)

301.71 cm³

Given,

Height =  8 cm

Slant height = 10 cm

We know that,

l² = r² + h²

Where, h = height

r = radius and l = slant height

10² = r² + 8²

= 100 = r² + 64

r²= 100 - 64 = 36

r = 6

We know that the volume of the cone = \(\frac{1}{3}\)πR²H  

= \(\frac{1}{3}\) × \(\frac{22}{7}\) × (6)² × 8 = 301.71 cm³