Practicing Success
A Carnot engine having an efficiency of 1/15 as heat engine, is used as a refrigerator. If the work done on the system is 23 J, the amount of energy absorbed from the reservoir at lower temperature is : |
100 J 322 J 90 J 99 J |
322 J |
\(\beta\) = \(\frac{1 - \eta }{\eta}\) \(\eta\) = 1/15 ; \(\beta\) = 14 = \(\frac{Q}{W}\) \(\beta\) = 14 = \(\frac{Q}{23}\) Q = 322 J |