A Carnot engine having an efficiency of 1/15 as heat engine, is used as a refrigerator. If the work done on the system is 23 J, the amount of energy absorbed from the reservoir at lower temperature is :
Answer & explanation
Correct answer: option 2
\(\beta\) = \(\frac{1 - \eta }{\eta}\)
\(\eta\) = 1/15 ;
\(\beta\) = 14 = \(\frac{Q}{W}\)
\(\beta\) = 14 = \(\frac{Q}{23}\)
Q = 322 J