Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

The  value of 18 ÷ 6 of 9 × [12 ÷ 3 of {16 × 2 ÷ (11 - 8)}] of (4 ÷ 2 of 8) is :

Options:

$\frac{9}{16}$

$\frac{3}{8}$

$\frac{1}{32}$

$\frac{81}{32}$

Correct Answer:

$\frac{1}{32}$

Explanation:

In this type of questions we will use BODMAS rule for calculation,

18 ÷ 6 of 9 × [12 ÷ 3 of {16 × 2 ÷ (11 - 8)}] of (4 ÷ 2 of 8)

= 18 ÷ 6 of 9 × [12 ÷ 3 of {16 × 2 ÷ 3}] of (4 ÷ 2 of 8)

= 18 ÷ 6 of 9 × [12 ÷ 3 of (16 × 2/3)] of (4 ÷ 2 of 8)

= 18 ÷ 6 of 9 × [12 ÷ (3 of 32/3)] of (4 ÷ 2 of 8)

= 18 ÷ 6 of 9 × [12 ÷ (3 × 32/3)] of (4 ÷ 2 of 8)

= 18 ÷ 6 of 9 × (12 ÷ 32) of (4 ÷ 2 of 8)

= 18 ÷ 6 of 9 × 3/8 of (4 ÷ 2 of 8)

= 18 ÷ 6 of 9 × 3/8 of (4 ÷ 16)

= 18 ÷ 6 of 9 × 3/8 × 1/4

= 18 ÷ 54 × 3/8 × 1/4

= 1/3 × 3/8 × 1/4

= 1/32