Practicing Success
If $A^2-A+I=0,$ then $A^{-1}$ is equal to : |
$A+I$ $A-I$ $A+2I$ $I-A$ |
$I-A$ |
The correct answer is Option (4) → $I-A$ $A^2-A+I=0$ multiplying by $A^{-1}$ $A^{-1}A^2-A^{-1}A+^{-1}I=0$ (we know that $A^{-1}A=I$ and $AI = A$) so $A-I+A^{-1}=0$ so $A^{-1}=I-A$ |