An electric current of 4.0 A flows through a 12 Ω resistor. The rate at which heat energy is produced in the resistor would be-
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 192 W
The rate of heat production is the power dissipated in the resistor, given by Joule’s law of heating.
\( \displaystyle P = I^{2}R \)
\( \displaystyle P = (4.0\,\mathrm{A})^{2} \times 12\,\Omega = 16 \times 12\,\mathrm{W} \)
\( \displaystyle P = 192\,\mathrm{W} \)