A motor is used to pump water from a depth of 5 m to fill a volume of 10 cubic meters in 5 minutes. If 50% of the power is wasted, what is the power of the motor? (Assume g = 10m/s²)

\(\frac{10000}{3} W\)

Density of water = 1000 kg/m³

Mass of water in 10m³ = 1000 x 10

    = 10000 kg

Volume of water filled in 1 s = \(\frac{10}{5*60}\)

    = \(\frac{1}{30}\) m³

Mass filled in 1 s = \(\frac{1}{30}\) x 1000

    =  \(\frac{100}{3}\) kg

Power = \(\frac{100}{3}\) x 10 x 5; ... [As : g = 10m/s²]

    = \(\frac{5000}{3}\) W

Since 50% of power is wasted, power of motor = \(\frac{5000}{3}\) x 2

    = \(\frac{10000}{3}\) W.