If 100.48 = x, 100.70 = y and xz = y2 then the value of z is close to ?
Answer & explanation
Correct answer: option 2
xz = y2
⇒ (10)(0.48z) = (10)(2 × 0.70) = (10)1.4
⇒ 0.48z = 1.40
z = \(\frac{148}{48}\)
z = 2.9
If 100.48 = x, 100.70 = y and xz = y2 then the value of z is close to ?
Correct answer: option 2
xz = y2
⇒ (10)(0.48z) = (10)(2 × 0.70) = (10)1.4
⇒ 0.48z = 1.40
z = \(\frac{148}{48}\)
z = 2.9