The area of a triangle with vertices (0, -3), (0, 3) and (k, 0) in 27 sq.units. The value of k is :
Answer & explanation
Correct answer: option 4
Points (0, -3), (0, 3), (k, 0)
area of triangle Δ = $\frac{1}{2}\begin{vmatrix}0&-3&1\\0&3&1\\k&0&1\end{vmatrix}$
expanding along $C_1$
$Δ =\frac{1}{2}k(-6)=27$
so $k = -9$