The following configuration of gate is equivalent to
Answer & explanation
Correct answer: option 2
$Y'=\overline{A+B}$ $Y=\overline{\overline{A+B}}=A+B$
Truth table of the given circuit is given by
| A | B | Y' | Y |
| 0 | 0 | 1 | 0 |
| 0 | 1 | 0 | 1 |
| 1 | 0 | 0 | 1 |
| 1 | 1 | 0 | 1 |
The following configuration of gate is equivalent to
Correct answer: option 2
$Y'=\overline{A+B}$ $Y=\overline{\overline{A+B}}=A+B$
Truth table of the given circuit is given by
| A | B | Y' | Y |
| 0 | 0 | 1 | 0 |
| 0 | 1 | 0 | 1 |
| 1 | 0 | 0 | 1 |
| 1 | 1 | 0 | 1 |