If \(\frac{a}{2}\) = \(\frac{b}{3}\) = \(\frac{c}{4}\) then find (\(\frac{a + b + c}{b}\))-1.

3 6 \(\frac{1}{3}\) \(\frac{1}{6}\)

\(\frac{1}{3}\)

Given, \(\frac{a}{2}\) = \(\frac{b}{3}\) = \(\frac{c}{4}\) Here we can directly conclude that  a = 2, b = 3, c = 4, hence ⇒ (\(\frac{a + b + c}{b}\))-1 = (\(\frac{2 + 3 + 4}{3}\))-1 = \(\frac{3}{9}\) = \(\frac{1}{3}\)