Practicing Success
The sequence of decay of a radioactive nucleus is:
If nucleon number and atomic number of R are 176 and 71 respectively. What are their values for P and S? |
$P-Z=72, A=172, S-Z=69, A=180$ $P-Z=72, A=180, S-Z=69, A=172$ $P-Z=76, A=180, S-Z=72, A=172$ $P-Z=72, A=178, S-Z=69, A=170$ |
$P-Z=72, A=180, S-Z=69, A=172$ |
The correct answer is Option (2) → $P-Z=72, A=180, S-Z=69, A=172$ |