Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Differential Equations

Question:

Differential equation associated with primitive y = Ae3x + Be5x :

Options:

$\frac{d^2 y}{d x^2}-8 \frac{d y}{d x}+15 y=0$

$\frac{d^2 y}{d x^2}+8 \frac{d y}{d x}-15 y=0$

$\frac{d^2 y}{d x^2}+8 \frac{d y}{d x}+y=0$

none of these

Correct Answer:

$\frac{d^2 y}{d x^2}-8 \frac{d y}{d x}+15 y=0$

Explanation:

y = Ae3x + Be5x

y' = 3 Ae3x + 5 Be5x

y'' = 9 Ae3x + 25 Be5x

therefore y'' − 8y + 15y = 0

Hence (1) is the correct answer.