\(\int \frac{\sin^6x}{\cos^8x}dx=\)
Answer & explanation
Correct answer: option 2
\(\int\frac{\sin^6x}{\cos^8x}dx=\int \tan^6x\sec^2xdx\)
Put \(\tan x=t\)
\(\int \frac{\sin^6x}{\cos^8x}dx=\)
Correct answer: option 2
\(\int\frac{\sin^6x}{\cos^8x}dx=\int \tan^6x\sec^2xdx\)
Put \(\tan x=t\)