Match List-I with List-II. List-I

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Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Probability Distributions

Question:

Match List-I with List-II.

List-I		List-II
(A)	Mean of binomial distribution is always	(I)	1
(B)	Probability function of binomial distribution with	(II)	greater than the variance
(C)	p(success)+p(failure)=	(III)	$\frac{1}{5}$
(D)	If for a binomial distribution the sum of the mean and variance for 5 trials is 1.8, then the probability of success is	(IV)	${^{16}C}_r (\frac{1}{4})^r(\frac{3}{4})^{16-r}, r=0, 1 ,....., 16$

Choose the correct answer from the options given below :

Options:

(A)-(II), (B)-(IV),(C)-(I),(D)-(III)

(A)-(I), (B)-(II),(C)-(III),(D)-(IV)

(A)-(III), (B)-(IV),(C)-(I),(D)-(II)

(A)-(I), (B)-(III),(C)-(II),(D)-(IV)

Correct Answer:

(A)-(II), (B)-(IV),(C)-(I),(D)-(III)

Explanation:

The correct answer is Option (1) → (A)-(II), (B)-(IV),(C)-(I),(D)-(III)

List-I		List-II
(A)	Mean of binomial distribution is always	(II)	greater than the variance
(B)	Probability function of binomial distribution with	(IV)	${^{16}C}_r (\frac{1}{4})^r(\frac{3}{4})^{16-r}, r=0, 1 ,....., 16$
(C)	p(success)+p(failure)=	(I)	1
(D)	If for a binomial distribution the sum of the mean and variance for 5 trials is 1.8, then the probability of success is	(III)	$\frac{1}{5}$