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a b c d |
b |
Potential difference across AB and CD is zero. Potential difference across BOC is same as if we place a single rod between B and C , hence length of the rod should be $ L = \sqrt { BO^2 + OC^2)} = \sqrt 2 m$ $ \Rightarrow \xi = BLV = 1\times \sqrt 2 \times 1 = \sqrt 2 = 1.41 V$ |
