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A small charged water drop with charge $1.5×10^{-6} C$ and mass 10 g is suspended in air in electric field E. The value of E is given by (Take acceleration due to gravity = $10 m s^{-2}$) |
$10.2 × 10^5 N/C$ $1.5 × 10^{-6} N/C$ $1.5 × 10^{-4} N/C$ $6. 67 × 10^4 N/C$ |
$6. 67 × 10^4 N/C$ |
The correct answer is Option (4) → $6. 67 × 10^4 N/C$ |
