A charged particle carrying charge q = 1 μC moves in a uniform magnetic field with velocity $v_1= 10^6 m/s$ at an angle of 45° with the x-axis in the xy-plane and experiences a force $F_1 = 0.4\sqrt{2} N$ along the negative z-axis. When the same particle moves with velocity $v_2 =10^6 m/s$ along the z-axis, it experiences a force $F_2$ in the y-direction. Find the magnitude of the magnetic field

0.8 T

The correct answer is Option (1) → 0.8 T