Match List-I with List-II
| List-I | List-II | ||
|---|---|---|---|
| (Equations) | (Solutions) | ||
| A. | \(2x-4=2-x\) | I. | \(x=3\) |
| B. | \(7-4x=0\) | II. | \(x=2\) |
| C. | \(\displaystyle\frac{x}{2}-3=0\) | III. | \(x=\displaystyle\frac{7}{4}\) |
| D. | \(2x+3=x+6\) | IV. | \(x=6\) |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → A-II, B-III, C-IV, D-I
Each equation is solved by bringing the \(x\) terms to one side and the numbers to the other; the solution is then matched in List-II.
(A) \(2x-4=2-x\) — this matches (II) \(x=2\).
\(3x=6\), so \(x=2\)
(B) \(7-4x=0\) — this matches (III) \(x=\frac{7}{4}\).
\(4x=7\), so \(x=\frac{7}{4}\)
(C) \(\frac{x}{2}-3=0\) — this matches (IV) \(x=6\).
\(\frac{x}{2}=3\), so \(x=6\)
(D) \(2x+3=x+6\) — this matches (I) \(x=3\).
\(2x-x=6-3\), so \(x=3\)