In a series LCR circuit, the voltage across R is 200 V, $C=5 μF, R=2 kΩ$. The resonant frequency ω is 100 rad/s. At resonance, the voltage across L is

200 V

The correct answer is Option (2) → 200 V

$V_R$ Voltage across $V_R = 200V$

Capacitance $C=5 μF=5×10^{−6} F$

Resistance $R=2 kΩ=2×10^3Ω$

Resonant frequency, $ω=100 rad/s$

Current in the circuit, $I=\frac{V_R}{R}$ [By ohm's law]

$=\frac{200}{2000}$

$=0.01A$

At resonance

$X_L=X_C=\frac{1}{ωC}=\frac{1}{100×5×10^{-6}}$

$=2000Ω$

Voltage across L is,

$V_L=10X_L=0.1×2000=200V$