The angle between the lines $2x = 3y = -

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Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Three-dimensional Geometry

Question:

The angle between the lines $2x = 3y = -z$ and $6x = -y = -4z$, is

Options:

0°

30°

45°

90°

Correct Answer:

90°

Explanation:

The equations of the given lines can be written in the from

$\frac{x}{3}=\frac{y}{2}=\frac{z}{-6}$ and $\frac{x}{1}=\frac{y}{-6}=\frac{z}{-3/2}$

Clearly, $3×1+2×(-6)-6×(-\frac{3}{2})=0$

So, given lines are perpendicular to each other.