Match the property given in List-I with

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Target Exam

CUET

Subject

Chemistry

Chapter

Inorganic: D and F Block Elements

Question:

Match the property given in List-I with the element given in List-II

List-I Property	List-II Element
(A) lanthanoid, which can show +2 oxidation state	(I) Pm
(B) Radioactive lanthanoid	(II) Lu
(C) Lanthanoid which has $4f^7$ electronic configuration in +3 oxidation state	(III) Eu
(D) Lanthanoid which has $4f^{14}$ electronic configuration in +3 oxidation state	(IV) Gd

Choose the correct answer from the options given below:

Options:

(A)-(III), (B)-(I), (C)-(IV), (D)-(II)

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

(A)-(II), (B)-(I), (C)-(IV), (D)-(III)

(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

Correct Answer:

(A)-(III), (B)-(I), (C)-(IV), (D)-(II)

Explanation:

The correct answer is Option (1) → (A)-(III), (B)-(I), (C)-(IV), (D)-(II)

List-I Property	List-II Element
(A) lanthanoid, which can show +2 oxidation state	(III) Eu
(B) Radioactive lanthanoid	(I) Pm
(C) Lanthanoid which has $4f^7$ electronic configuration in +3 oxidation state	(IV) Gd
(D) Lanthanoid which has $4f^{14}$ electronic configuration in +3 oxidation state	(II) Lu

Quick explanation:

Europium (Eu) → Easily forms stable Eu²⁺ (half-filled f⁷ stability when it loses one more electron from Eu³⁺).
Promethium (Pm) → No stable isotope → all are radioactive.
Gadolinium (Gd) → Gd³⁺ = [Xe] 4f⁷ → exactly half-filled.
Lutetium (Lu) → Lu³⁺ = [Xe] 4f¹⁴ → completely filled 4f subshell.