If $ X + \frac{1}{x} = 6$, then find the value of $\frac{3x}{2x^2-5x+2}$

1 $\frac{3}{7}$ $\frac{2}{3}$ 0

$\frac{3}{7}$

$ X + \frac{1}{x} = 6$ Find $\frac{3x}{2x^2-5x+2}$  $ X + \frac{1}{x} = 6$ = x2 + 1 = 6x  x2 = 6x - 1 Put x2 in $\frac{3x}{2x^2-5x+2}$ =  $\frac{3x}{2(6x - 1) -5x+2}$ = $\frac{3x}{12x - 2 -5x+2}$ = $\frac{3}{7}$