If $ X + \frac{1}{x} = 6$, then find the value of $\frac{3x}{2x^2-5x+2}$
Answer & explanation
Correct answer: option 2
$ X + \frac{1}{x} = 6$
Find $\frac{3x}{2x^2-5x+2}$
$ X + \frac{1}{x} = 6$ = x2 + 1 = 6x
x2 = 6x - 1
Put x2 in $\frac{3x}{2x^2-5x+2}$
= $\frac{3x}{2(6x - 1) -5x+2}$
= $\frac{3x}{12x - 2 -5x+2}$
= $\frac{3}{7}$