If x - \(\frac{1}{x}\) = 4\(\sqrt{6}\) then find the value of  x3 + \(\frac{1}{x^3}\)

1000 970 1030 956

970

⇒ If x - \(\frac{1}{x}\) = a then x + \(\frac{1}{x}\) = \(\sqrt {a^2 + 4}\) and If x + \(\frac{1}{x}\) = a then ⇒ x3 + \(\frac{1}{x^3}\) = a3 - 3a ATQ, x - \(\frac{1}{x}\) = 4\(\sqrt{6}\), then  ⇒ x + \(\frac{1}{x}\) = \(\sqrt {(4\sqrt{6})^2 + 4}\) = 10 ⇒ x3 + \(\frac{1}{x^3}\) = 103 - 3 × 10 = 970