Consider a random sample of 10 students having 116 cm as mean height and standard deviation as 9.798 cm. If the suggested mean height of the students population is 110 cm then the t-test statistic of the sample is: [given $\frac{\sqrt{10}}{9.798}= 0.3227]$

1.93

The correct answer is Option (1) → 1.93

Given:

Sample mean: $\bar{x} = 116$ cm

Sample standard deviation: $s = 9.798$ cm

Sample size: $n = 10$

Population mean: $\mu_0 = 110$ cm

t-test statistic formula:

$t = \frac{\bar{x} - \mu_0}{s / \sqrt{n}}$

Substitute the values:

$t = \frac{116 - 110}{9.798 / \sqrt{10}}$

$t = \frac{6}{9.798 / 3.1623}$

$t = \frac{6}{3.096} \approx 1.938$

Therefore, the t-test statistic is approximately $t \approx 1.938$