The product of two numbers is 2028 and HCF is 13.  How many possible pairs of such type?

1 2 3 4

2

Product of two factors = \(\frac{Product\;of\;two\;number}{HCF^2}\)                                 = \(\frac{2028}{169}\) = 12 Product of two factors possibilities:- 1, 12 3, 4 ∴ 2 possibilities