Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B2

Chapter

Probability Distributions

Question:

Suppose that X has Poisson distribution. If $P(X=2)=\frac{2}{3} P(X=1)$, then $P(X=0)$ is equal to

Options:

$e^{\frac{4}{3}}$

$e^{-1}$

$e^{\frac{-4}{3}}$

$e^{\frac{-3}{4}}$

Correct Answer:

$e^{\frac{-4}{3}}$

Explanation:

The correct answer is Option (3) → $e^{\frac{-4}{3}}$