CUET Preparation Today
CUET
-- Applied Mathematics - Section B2
Probability Distributions
Suppose that X has Poisson distribution. If $P(X=2)=\frac{2}{3} P(X=1)$, then $P(X=0)$ is equal to
$e^{\frac{4}{3}}$
$e^{-1}$
$e^{\frac{-4}{3}}$
$e^{\frac{-3}{4}}$
The correct answer is Option (3) → $e^{\frac{-4}{3}}$