A kite flying at a height of 120 m is attached to a string which makes an angle of 60o with the horizontal. What is the length (in m) of the string?

$90\sqrt{3}$ $75\sqrt{3}$ $84\sqrt{3}$ $80\sqrt{3}$

$80\sqrt{3}$

⇒ Sin \({60}^\circ\) = \(\frac{120}{AC}\) ⇒ \(\frac{√3}{2}\) = \(\frac{120}{AC}\) ⇒ AC = \(\frac{120 × 2}{√3}\) ⇒ AC = \(\frac{240}{√3}\) ⇒ AC = 80√3