The area bounded between the parabola x2 = \(\frac{y}{4}\) and x2 = 9y and the straight line y = 2 is :
Answer & explanation
Correct answer: option 1
Area = 2\(\int_{0}^{2}(3\sqrt{y}-\frac{1}{2}\sqrt{y}) dy\)
= \(\frac{20\sqrt{2}}{3}\)
The area bounded between the parabola x2 = \(\frac{y}{4}\) and x2 = 9y and the straight line y = 2 is :
Correct answer: option 1
Area = 2\(\int_{0}^{2}(3\sqrt{y}-\frac{1}{2}\sqrt{y}) dy\)
= \(\frac{20\sqrt{2}}{3}\)