The area bounded between the parabola x2 = \(\frac{y}{4}\) and x2 = 9y and the straight line y = 2 is :

\(\frac{20\sqrt{2}}{3}\) 10\(\sqrt{2}\) 20\(\sqrt{2}\) \(\frac{10\sqrt{2}}{3}\)

\(\frac{20\sqrt{2}}{3}\)

Area = 2\(\int_{0}^{2}(3\sqrt{y}-\frac{1}{2}\sqrt{y}) dy\)         = \(\frac{20\sqrt{2}}{3}\)