The maximum value of the objective function $Z = 8x + 2y$ of an L.P.P. subject to constraints $2x + y ≤3,2x+3y≤6,x≥0, y ≥ 0$ is: |
12 9 16 6 |
12 |
The correct answer is Option (1) → 12 $\text{Objective: }Z=8x+2y$ $\text{Constraints: }2x+y\le 3,\;2x+3y\le 6,\;x\ge0,\;y\ge0$ $\text{Corner points: }(0,0),\;(0,2),\;(0.75,1.5),\;(1.5,0)$ $Z(0,0)=0$ $Z(0,2)=4$ $Z\left(\frac{3}{4},\frac{3}{2}\right)=8\cdot\frac{3}{4}+2\cdot\frac{3}{2}=6+3=9$ $Z(1.5,0)=12$ The maximum value of $Z$ is $12$. |