Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

Options:

a

b

c

d

Correct Answer:

d

Explanation:

$\text{Initial Energy Stored in capacitor is } = \frac{1}{2} KCV^2$

$\text{Final Energy Stored in capacitor is } = \frac{1}{2} KCV^2$

$\text{Net work done }=0$