Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

System of Particle and Rotational Motion

Question:

Masses 1 kg, 1.5 kg, 2 kg, and “M” kg are situated at (2,1,1), (1,2,1), (2,-2,1) and (-1,4,3). What is the value of “M” if their centre of mass is at (1,1,3/2)?

Options:

2 kg

1 kg

1.5 kg

2.5 kg

Correct Answer:

1.5 kg

Explanation:

Sum of masses = 1 + 1.5 + 2 + M = 4.5 + M

x-coordinate : (1 x 2 + 1.5 x 1 + 2 x 2 – M)/(4.5 + M) = 1

4.5 + M = 7.5 – M

2M = 3

M = 1.5 kg