The differential equation representing family of circles with centre at point (4, 0) is :
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\frac{dy}{dx}=\frac{4-x}{y}$
$(x-4)^2+(y-0)^2=R^2$ → radius (arbitrary constant)
Differentiate w.r.t. x
$2(x-4)+2y\frac{dy}{dx}=0⇒\frac{dy}{dx}=\frac{4-x}{y}$