A ladder leaning against a wall makes an angle θ with the horizontal ground such that $\tan \theta = \frac{12}{5}.$ If the height of the top of the ladder from the wall is 24 m, then what is the distance (in m) of the foot of the ladder from the wall?

10

⇒ tan \(\theta \) = \(\frac{12}{5}\)

⇒ 12 units = 24m

⇒ 1 unit = 2m

⇒ BC = 5 units = 5 x 2 = 10m

Therefore, the distance of the foot of the ladder from the wall is 10m.