Practicing Success
The interval in which the function $f(x)=10-6 x-2 x^2$ is decreasing is: |
$\left(\frac{-3}{2}, \frac{3}{2}\right)$ $\left(-\infty, \frac{-3}{2}\right)$ $\left(\frac{-3}{2}, \infty\right)$ $\left(-\infty, \frac{3}{2}\right)$ |
$\left(\frac{-3}{2}, \infty\right)$ |
The correct answer is Option (3) - $\left(\frac{-3}{2}, \infty\right)$ $f(x)=10-6 x-2 x^2$ $f'(x)=-6-4x=0⇒4x=-6$ $x=\frac{-3}{2}$ |