The interval in which the function $f(x)=10-6 x-2 x^2$ is decreasing is:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) - $\left(\frac{-3}{2}, \infty\right)$
$f(x)=10-6 x-2 x^2$
$f'(x)=-6-4x=0⇒4x=-6$
$x=\frac{-3}{2}$
The interval in which the function $f(x)=10-6 x-2 x^2$ is decreasing is:
Correct answer: option 3
The correct answer is Option (3) - $\left(\frac{-3}{2}, \infty\right)$
$f(x)=10-6 x-2 x^2$
$f'(x)=-6-4x=0⇒4x=-6$
$x=\frac{-3}{2}$