What is the value of $\frac{sinθ+cosθ}{sinθ-cosθ}+\frac{sinθ-cosθ}{sinθ+cosθ}$?

$1/(sin^2θ-cos^2θ)$ $2(sin^2θ-cos^2θ)$ $2/(sin^2θ-cos^2θ)$ $sin^2θ-cos^2θ$

$2/(sin^2θ-cos^2θ)$

\(\frac{sinθ +cosθ }{sinθ - cosθ }\) + \(\frac{sinθ -cosθ }{sinθ + cosθ }\) = \(\frac{(sinθ +cosθ)² + (sinθ - cosθ)² }{sin²θ - cos²θ }\) = \(\frac{(sin²θ +cos²θ +2sinθ.cosθ ) + (sin²θ + cos²θ -2sinθ.cosθ ) }{sin²θ - cos²θ }\) { using , sin²θ +cos²θ = 1 } = \(\frac{2 }{sin²θ - cos²θ }\)