What is the value of $\frac{sinθ+cosθ}{sinθ-cosθ}+\frac{sinθ-cosθ}{sinθ+cosθ}$?
Answer & explanation
Correct answer: option 3
\(\frac{sinθ +cosθ }{sinθ - cosθ }\) + \(\frac{sinθ -cosθ }{sinθ + cosθ }\)
= \(\frac{(sinθ +cosθ)² + (sinθ - cosθ)² }{sin²θ - cos²θ }\)
= \(\frac{(sin²θ +cos²θ +2sinθ.cosθ ) + (sin²θ + cos²θ -2sinθ.cosθ ) }{sin²θ - cos²θ }\)
{ using , sin²θ +cos²θ = 1 }
= \(\frac{2 }{sin²θ - cos²θ }\)