Practicing Success
Practicing Success
CUET Preparation Today
$\int\limits_{-π/2}^{π/2}\frac{e^{|\sin x|}.\cos x}{(1+e^{\tan x})}dx$ is equal to: |
e + 1 1 – e e – 1 None of these |
e – 1 |
$I=\int\limits_{0}^{π/2}(\frac{e^{\sin x}.\cos x}{1+e^{\tan x}}+\frac{e^{|\sin (-x)|}\cos x}{1+e^{\tan (-x)}})dx=\int\limits_{0}^{π/2}e^{\sin x}.\cos x\,dx=\int\limits_{0}^{1}e^t\,dt=e-1$ |
