Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

Find the value of  \(\frac{sin90°\;+\;sin45°}{cosec90°\;+\;tan45°}\) .

Options:

\(\frac{2+\sqrt {2}}{6}\)

\(\frac{2+\sqrt {2}}{2}\)

\(\frac{2+\sqrt {2}}{4}\)

\(\frac{2+\sqrt {2}}{3}\)

Correct Answer:

\(\frac{2+\sqrt {2}}{4}\)

Explanation:

⇒ \(\frac{sin90°\;+\;sin45°}{cosec90°\;+\;tan45°}\)

= \(\frac{1+\frac{1}{\sqrt {2}}}{1+1}\)

= \(\frac{\sqrt {2}+1}{2\sqrt {2}}\)

= \(\frac{\sqrt {2}+1}{2\sqrt {2}}\)×\(\frac{\sqrt {2}}{\sqrt {2}}\)

\(\frac{2+\sqrt {2}}{4}\)