Find the value of \(\frac{sin90°\;+\;sin45°}{cosec90°\;+\;tan45°}\) .
Answer & explanation
Correct answer: option 3
⇒ \(\frac{sin90°\;+\;sin45°}{cosec90°\;+\;tan45°}\)
= \(\frac{1+\frac{1}{\sqrt {2}}}{1+1}\)
= \(\frac{\sqrt {2}+1}{2\sqrt {2}}\)
= \(\frac{\sqrt {2}+1}{2\sqrt {2}}\)×\(\frac{\sqrt {2}}{\sqrt {2}}\)
= \(\frac{2+\sqrt {2}}{4}\)