If $xsin^3θ+ycos^3θ = sinθ cosθ$ and $x sinθ = y cos θ$, then the value of $x^2 + y^2$ is :

0 4 1 2

1

Given :- x sin³θ + y cos³θ = sinθ.cosθ---(1)   and xsinθ = ycosθ  ---(2) ycosθ. sin²θ + y cos³θ = sinθ.cosθ ycosθ. ( sin²θ + cos²θ ) = sinθ.cosθ { Using sin²θ + cos²θ  = 1 } y = sinθ Putting value of y in equation 2. xsinθ = sinθ. cosθ x = cosθ x² + y² = sin²θ + cos²θ = 1