Match List I with List II

Choose the correct answer from the options given below:

A-II, B-IV, C-I, D-III

The correct answer is option 1.  A-II, B-IV, C-I, D-III.

A. \(V^{2+}\):

Number of unpaired electrons = 3

So the magnetic moment will be

\(\mu = \sqrt{n (n + 2)}\)

or, \(\mu = \sqrt{3 (3 + 2)}\)

or, \(\mu =\sqrt{15}\)

or, \(\mu = 3.87\)

Which matches with II from List II.

B. \(Ni^{2+}\)

Number of unpaired electrons = 2

So the magnetic moment will be

\(\mu = \sqrt{2 (2 + 2)}\)

or, \(\mu =\sqrt{8}\)

or, \(\mu = 2.84\)

Which matches with IV from List II.

C. \(Cu^{2+}\)

Number of unpaired electrons = 1

So the magnetic moment will be

\(\mu = \sqrt{1 (1 + 2)}\)

or, \(\mu =\sqrt{5}\)

or, \(\mu = 1.73\)

Which matches with I from List II.

D. \(Cr^{2+}\)

Number of unpaired electrons = 4

So the magnetic moment will be

\(\mu = \sqrt{4 (4 + 2)}\)

or, \(\mu =\sqrt{24}\)

or, \(\mu = 4.90\)

Which matches with III from List II.