What is the r.m.s. value of current where $ I = \sqrt 2 sin (\omega t + \frac{\pi}{3})$
Answer & explanation
Correct answer: option 2
$ I_{rms} = \frac{I_0}{\sqrt 2} = 1A$
$I_0 = \sqrt 2 A$
What is the r.m.s. value of current where $ I = \sqrt 2 sin (\omega t + \frac{\pi}{3})$
Correct answer: option 2
$ I_{rms} = \frac{I_0}{\sqrt 2} = 1A$
$I_0 = \sqrt 2 A$