Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Alternating Current

Question:

What is the r.m.s. value of current where $  I = \sqrt 2 sin (\omega t + \frac{\pi}{3})$

                       

Options:

$\sqrt 2 A$

1A

$\frac{1}{\sqrt 2}A$

2A

Correct Answer:

1A

Explanation:

$ I_{rms} = \frac{I_0}{\sqrt 2} = 1A$

$I_0 = \sqrt 2 A$