Two coherent light beams of intensity 2I and 18I are superposed with each other. The maximum and minimum possible intenstities in the resulting beam are |
36I, 4I 32I, 8I 324I, 4I 400I, 324I |
32I, 8I |
The correct answer is Option (2) → 32I, 8I $I_{max}∝|E_{max}|^2=(E_1+E_2)^2$ where, $I_{max}$ = max. intensity $I_{max}=(\sqrt{2I}+\sqrt{18I})^2$ $=I(\sqrt{2}+3\sqrt{2})^2=I(4\sqrt{2})^2$ $=32I$ $I_{min}∝|E_{min}|^2=(E_1-E_2)^2$ $=(\sqrt{2I}+\sqrt{18I})^2$ $=8I$ |