A wheel has angular acceleration of 3.0 rad/sec2 and an initial angular speed of 2.00 rad/sec. In a time of 2 sec it has rotated through an angle (in radian) of :
Answer & explanation
Correct answer: option 1
Since, \(\theta = \omega_o t + \frac{1}{2} \alpha t^2\)
Where a is angular acceleration, \(\omega\)0 is the initial angular speed.
t = 2s
\(\theta = 2 × 2 + \frac{1}{2}×3(2)^2 = 10 rad\)