If 'a' is a natural number, then (9a2 + 9a) is always divisible by?
Answer & explanation
Correct answer: option 3
Put a = 1 (as 1 is a natural number)
9 × 12 + 9 × 1 = 18 which is divisible by option 3 (9 and 18, both)
If 'a' is a natural number, then (9a2 + 9a) is always divisible by?
Correct answer: option 3
Put a = 1 (as 1 is a natural number)
9 × 12 + 9 × 1 = 18 which is divisible by option 3 (9 and 18, both)