If the letters of word ‘REGULATIONS’ be arranged at random, the probability that there will be exactly 4 letters between R and E is:
Answer & explanation
Correct answer: option 1
P(required) = $\frac{({^9C}_4.4!)×2!×6!}{11!}=\frac{6}{55}$
If the letters of word ‘REGULATIONS’ be arranged at random, the probability that there will be exactly 4 letters between R and E is:
Correct answer: option 1
P(required) = $\frac{({^9C}_4.4!)×2!×6!}{11!}=\frac{6}{55}$