Electron is accelerated by 100 volt potential difference. Its wavelength will be comparable to that of :
Answer & explanation
Correct answer: option 3
The correct answer is option (3) : X-rays
de-Broglie wavelength of electron =$\frac{1.227}{\sqrt{V}}nm$
$=\frac{1.227}{\sqrt{100}}$
$=0.1227\, nm$
Range of X-rays (0.01 - 10 ) nm