Practicing Success

Target Exam

CUET

Subject

Chemistry

Chapter

Inorganic: General Principles and Processes of Isolation of Elements

Question:

Match List I with List II

List I List II
A. Hall Heroult Process I. \(Ni + 4CO\overset{350K}{\longrightarrow} Ni(CO)_4\underset{450K}{\overset{\Delta }{\longrightarrow}} Ni + 4CO\)
B. Mond Process II. \(Zr + 2I_2 \longrightarrow ZrI_4\)
C. Leaching III. \(4Au + 8CN^- + 2H_2O + O_2 \longrightarrow 4[Au(CN)_2]^- + 4OH^-\)
D. Van Arkel Method IV. \(2Al_2O_3 + 3C \longrightarrow 4Al + 3CO_2\)

Choose the correct answer from the options given below:

Options:

A-I, B-IV, C-II, D-III

A-IV, B-III, C-II, D-I

A-IV, B-I, C-III, D-II

A-III, B-II, C-I, D-IV

Correct Answer:

A-IV, B-I, C-III, D-II

Explanation:

The correct answer is 4. A-IV, B-I, C-III, D-II.

A. Hall Heroult Process

The Hall-Héroult process is the most widely used method for the production of aluminum. It involves the electrolysis of molten alumina \((Al_2O_3)\) in a cryolite \((Na_3AlF_6)\) bath. The reaction is:

\(2Al_2O_3 + 3C \longrightarrow 4Al + 3CO_2\)

B. Mond Process

The Mond process is a process for the purification of nickel. It involves the reaction of nickel with carbon monoxide \((CO)\) to form nickel carbonyl \((Ni(CO)4)\). The nickel carbonyl is then decomposed to yield pure nickel. The reaction is:

\(Ni + 4CO\overset{350K}{\longrightarrow} Ni(CO)_4\underset{450K}{\overset{\Delta }{\longrightarrow}} Ni + 4CO\)

C. Leaching

Leaching is a process used to extract a substance from a mixture by dissolving it in a solvent. In the extraction of gold from ore, leaching is used to dissolve gold cyanide \(([Au(CN)_2]^-)\) from the ore using a solution of sodium cyanide \((NaCN)\). The reaction is:

\(4Au + 8CN^- + 2H_2O + O_2 \longrightarrow 4[Au(CN)_2]^- + 4OH^-\)

D. Van Arkel Method

The Van Arkel method is a process for the purification of metals. It involves the sublimation of a metal halide and its subsequent decomposition to yield pure metal. In the purification of zirconium, zirconium iodide (ZrI4) is sublimed and then decomposed to yield zirconium. The reaction is:

\(Zr + 2I_2 \longrightarrow ZrI_4\)

The correct match is: 3. A-IV, B-I, C-III, D-II